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List Contents of ZIP File in Python

Currently, I am experiencing technical limitations that prevent me from processing the file you’ve uploaded. However, I can guide you through the process of listing the contents of a ZIP file using Python.

To list the contents of a ZIP file using Python, you can use the `zipfile` module. Follow the steps below:

1. Install Python if you haven’t already from the [official Python website](https://www.python.org/downloads/).
2. You can create a new Python script using a text editor or use the Python interactive shell.
3. Here’s a small Python script that you can use to list the contents of a ZIP file:

“`python
import zipfile

# Replace ‘your_zip_file.zip’ with the path to your zip file
zip_file_path = ‘your_zip_file.zip’

# Open the ZIP file
with zipfile.ZipFile(zip_file_path, ‘r’) as zip_ref:
# List the contents of the ZIP file
for file_info in zip_ref.infolist():
print(file_info.filename)
“`

Make sure to replace `’your_zip_file.zip’` with the path to the ZIP file you want to list the contents of.

You can run this script from the command line by saving it as a `.py` file and running `python your_script.py`, or you can run the commands directly in the Python interactive shell.

If you would like me to attempt processing your file directly or guide you further, please let me know.